Interesting Math Problems
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Re: Interesting Math Problems
Ain't that the truth!

I didn't answer, as I've seen variants of this problem before. In fact, a logic professor used a variant as an "extra" credit question. We could either do the test as is, or just answer a similar problem instead, either way for full credit. Almost everyone (including myself) just did the test as is.

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Re: Interesting Math Problems
It was not specified the start and stop points were the ends of the rod.Animal wrote: ↑Fri Mar 11, 2022 3:32 pm the solution looks much more complicated than it is.
Basically, for each wrap the string has to make a hypotenuse of a right triangle formed by the Circumference and the Pitch (Length/# Turns).
In this case that is the hypotenuse of a right triangle with leg 4 and 3. That hypotenuse is 5. Now how many times does it do that? In this case it makes 4 turns. so that is 4 x 5 = 20.
My 16 is correct. My 48 is incorrect it should be 96.
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Re: Interesting Math Problems
QillerDaemon wrote: ↑Fri Mar 11, 2022 5:04 am A string is wrapped around a rod exactly four times end to end. The rod is 12 units long and has a circumference of 4 units. What is the length of the string?
Edit: the string wraps around the rod exactly like the red strip around the barber's pole, screw thread like. Just so we're clear, since I haven't included a picture.
By the way, wrong answers so far. Hint: split the rod and thread length-wise and unfold.
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Re: Interesting Math Problems
I agree. The problem description was highly flawed. Which is why I typically don't participate in these sort of posts.Antknot wrote: ↑Fri Mar 11, 2022 5:08 pmIt was not specified the start and stop points were the ends of the rod.Animal wrote: ↑Fri Mar 11, 2022 3:32 pm the solution looks much more complicated than it is.
Basically, for each wrap the string has to make a hypotenuse of a right triangle formed by the Circumference and the Pitch (Length/# Turns).
In this case that is the hypotenuse of a right triangle with leg 4 and 3. That hypotenuse is 5. Now how many times does it do that? In this case it makes 4 turns. so that is 4 x 5 = 20.
My 16 is correct. My 48 is incorrect it should be 96.
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Re: Interesting Math Problems
winner, winner! chicken dinner!
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Re: Interesting Math Problems
In all fairness, that was an edit when I realized some were conceptualizing the problem incorrectly. So I can see where the answers went awry.Animal wrote: ↑Fri Mar 11, 2022 5:14 pmQillerDaemon wrote: ↑Fri Mar 11, 2022 5:04 am A string is wrapped around a rod exactly four times end to end. The rod is 12 units long and has a circumference of 4 units. What is the length of the string?
Edit: the string wraps around the rod exactly like the red strip around the barber's pole, screw thread like. Just so we're clear, since I haven't included a picture.
By the way, wrong answers so far. Hint: split the rod and thread length-wise and unfold.
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Re: Interesting Math Problems
The answer is, and always will be, 42.
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Re: Interesting Math Problems
A to power B = 343, B to power C = 10, A to power C = 7. What is B to power B?
(edit: hint, the values of A, B, and C really don't matter, other than they don't equal each other)
(edit: hint, the values of A, B, and C really don't matter, other than they don't equal each other)
If you can't be a good example, you can still serve as a horrible warning.
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。
“All mushrooms are edible. Some even more than once!”
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Re: Interesting Math Problems
10 to the 10th power. Or 10,000,000,000QillerDaemon wrote: ↑Sat Mar 19, 2022 7:44 pm A to power B = 343, B to power C = 10, A to power C = 7. What is B to power B?
(edit: hint, the values of A, B, and C really don't matter, other than they don't equal each other)
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Re: Interesting Math Problems
Buzz! You're way out of degree. Think about what the number 343 is.Animal wrote: ↑Sat Mar 19, 2022 8:01 pm10 to the 10th power. Or 10,000,000,000QillerDaemon wrote: ↑Sat Mar 19, 2022 7:44 pm A to power B = 343, B to power C = 10, A to power C = 7. What is B to power B?
(edit: hint, the values of A, B, and C really don't matter, other than they don't equal each other)
If you can't be a good example, you can still serve as a horrible warning.
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。
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Re: Interesting Math Problems
What kind of power? Gas, electric, nuclear?QillerDaemon wrote: ↑Sat Mar 19, 2022 7:44 pm A to power B = 343, B to power C = 10, A to power C = 7. What is B to power B?
(edit: hint, the values of A, B, and C really don't matter, other than they don't equal each other)
du.du.du.dude looks like a lady
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Re: Interesting Math Problems
Yeah, I just looked at it again and I wasn't thinking.QillerDaemon wrote: ↑Sat Mar 19, 2022 8:20 pmBuzz! You're way out of degree. Think about what the number 343 is.Animal wrote: ↑Sat Mar 19, 2022 8:01 pm10 to the 10th power. Or 10,000,000,000QillerDaemon wrote: ↑Sat Mar 19, 2022 7:44 pm A to power B = 343, B to power C = 10, A to power C = 7. What is B to power B?
(edit: hint, the values of A, B, and C really don't matter, other than they don't equal each other)
A^B must be 7^3. So, A is 7 and B is 3.
A^C must be 7^1. So, A is 7 and C is 1.
B^C must be B^1 = 10. So B = 10.
Now, I guess that means we have to do B^B = 10^3? or 1,000? I was confused that there are two different numbers for B.
It would make more sense to use Capital B and Lower case B.
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Re: Interesting Math Problems
You have the right numerical answer, but you're still worrying about the actual values of A, B, and C when you don't need to. What their values are don't matter, they can be anything using the exponential change of base rule (except 1). Try again, but consider the exponential power rule instead. That way, again the variables can have any actual value, not just what you figured them to be. You'll still come to the same answer.Animal wrote: ↑Sat Mar 19, 2022 8:29 pm Yeah, I just looked at it again and I wasn't thinking.
A^B must be 7^3. So, A is 7 and B is 3.
A^C must be 7^1. So, A is 7 and C is 1.
B^C must be B^1 = 10. So B = 10.
Now, I guess that means we have to do B^B = 10^3? or 1,000? I was confused that there are two different numbers for B.
It would make more sense to use Capital B and Lower case B.
If you can't be a good example, you can still serve as a horrible warning.
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。
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Re: Interesting Math Problems
Well, I don't follow that, but it seems to me that in your question B means one thing if it is being raised to a power and B means something different if it represents a power that it is raising something else to. So B^B = 10^3 or 1,000.QillerDaemon wrote: ↑Sat Mar 19, 2022 9:10 pmYou have the right numerical answer, but you're still worrying about the actual values of A, B, and C when you don't need to. What their values are don't matter, they can be anything using the exponential change of base rule (except 1). Try again, but consider the exponential power rule instead. That way, again the variables can have any actual value, not just what you figured them to be. You'll still come to the same answer.Animal wrote: ↑Sat Mar 19, 2022 8:29 pm Yeah, I just looked at it again and I wasn't thinking.
A^B must be 7^3. So, A is 7 and B is 3.
A^C must be 7^1. So, A is 7 and C is 1.
B^C must be B^1 = 10. So B = 10.
Now, I guess that means we have to do B^B = 10^3? or 1,000? I was confused that there are two different numbers for B.
It would make more sense to use Capital B and Lower case B.
I could argue that B^B might also equal 3^10 or 59,049 but I wouldn't guess that answer since that means switching the B's in the way they are used in the question. Same reason I rule out 10^10 (my first guess) or 3^3 for an answer.
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Re: Interesting Math Problems
J.A.F.U.Q.M.Q.QillerDaemon wrote: ↑Sat Mar 19, 2022 9:10 pmYou have the right numerical answer, but you're still worrying about the actual values of A, B, and C when you don't need to. What their values are don't matter, they can be anything using the exponential change of base rule (except 1). Try again, but consider the exponential power rule instead. That way, again the variables can have any actual value, not just what you figured them to be. You'll still come to the same answer.Animal wrote: ↑Sat Mar 19, 2022 8:29 pm Yeah, I just looked at it again and I wasn't thinking.
A^B must be 7^3. So, A is 7 and B is 3.
A^C must be 7^1. So, A is 7 and C is 1.
B^C must be B^1 = 10. So B = 10.
Now, I guess that means we have to do B^B = 10^3? or 1,000? I was confused that there are two different numbers for B.
It would make more sense to use Capital B and Lower case B.
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Re: Interesting Math Problems
You have to divide by E.I.E.I.O.Antknot wrote: ↑Sat Mar 19, 2022 9:47 pmJ.A.F.U.Q.M.Q.QillerDaemon wrote: ↑Sat Mar 19, 2022 9:10 pmYou have the right numerical answer, but you're still worrying about the actual values of A, B, and C when you don't need to. What their values are don't matter, they can be anything using the exponential change of base rule (except 1). Try again, but consider the exponential power rule instead. That way, again the variables can have any actual value, not just what you figured them to be. You'll still come to the same answer.Animal wrote: ↑Sat Mar 19, 2022 8:29 pm Yeah, I just looked at it again and I wasn't thinking.
A^B must be 7^3. So, A is 7 and B is 3.
A^C must be 7^1. So, A is 7 and C is 1.
B^C must be B^1 = 10. So B = 10.
Now, I guess that means we have to do B^B = 10^3? or 1,000? I was confused that there are two different numbers for B.
It would make more sense to use Capital B and Lower case B.
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Re: Interesting Math Problems
What I meant was that the actual number values of the three variables are A, B, and C. Nothing more or less. Whether the variable is being used as the base or the exponent, its value is exactly the same and meaningless. As my old math professor used to say "you got the right answer, but you didn't use the information provided in the correct manner." This problem is strictly an algebraic question using the power rule and the info provided, *not* to figure out what the value of A, B, and C each is.Animal wrote: ↑Sat Mar 19, 2022 9:20 pm Well, I don't follow that, but it seems to me that in your question B means one thing if it is being raised to a power and B means something different if it represents a power that it is raising something else to. So B^B = 10^3 or 1,000.
I could argue that B^B might also equal 3^10 or 59,049 but I wouldn't guess that answer since that means switching the B's in the way they are used in the question. Same reason I rule out 10^10 (my first guess) or 3^3 for an answer.
Note: I'm changing the notation a little. I wish we had sub- and superscripts in phpBB, we don't. So instead of saying "A to power B", I'm changing it to "A power B", with "power" signifying the exponential power. Maybe that clarifies things?
The original question is "A power B = 343, B power C = 10, A power C = 7. What is B power B?" In all actuality, the values of A, B, and C can be anything, and ultimately what the value of B is, isn't of any concern, it's what the value of B power B is that matters.
343 is 7 cubed, 7 power 3. Now A power B = 343 = 7 power 3. We do not necessarily know that A = 7 or that B = 3 at this point.
Substitute into that A power C = 7 ("using the info provided"), and you get A power B = (A power C) power 3. Use the power rule to make A power B = A power 3C. Now you have an equation with the same base (whatever that value of the base is), so the two powers have to be equal.
So B = 3C. Go back to B power B. Substitute in 3C for the exponent B: B power B = B power 3C. Use the power rule again, using its inverse, to get B power B = (B power C) power 3. The second given equation is B power C = 10, substitute that into the parentheses.
B power B = (10) power 3. At no time do we know the actual values of A, B, or C, nor care.
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Re: Interesting Math Problems
you actually do care what A,B, and C are because you have to remember to keep them in the right places as they relate to the equation. I follow what you are doing, but its just a much more complicated way of doing what I did.QillerDaemon wrote: ↑Sat Mar 19, 2022 10:45 pmWhat I meant was that the actual number values of the three variables are A, B, and C. Nothing more or less. Whether the variable is being used as the base or the exponent, its value is exactly the same and meaningless. As my old math professor used to say "you got the right answer, but you didn't use the information provided in the correct manner." This problem is strictly an algebraic question using the power rule and the info provided, *not* to figure out what the value of A, B, and C each is.Animal wrote: ↑Sat Mar 19, 2022 9:20 pm Well, I don't follow that, but it seems to me that in your question B means one thing if it is being raised to a power and B means something different if it represents a power that it is raising something else to. So B^B = 10^3 or 1,000.
I could argue that B^B might also equal 3^10 or 59,049 but I wouldn't guess that answer since that means switching the B's in the way they are used in the question. Same reason I rule out 10^10 (my first guess) or 3^3 for an answer.
Note: I'm changing the notation a little. I wish we had sub- and superscripts in phpBB, we don't. So instead of saying "A to power B", I'm changing it to "A power B", with "power" signifying the exponential power. Maybe that clarifies things?
The original question is "A power B = 343, B power C = 10, A power C = 7. What is B power B?" In all actuality, the values of A, B, and C can be anything, and ultimately what the value of B is, isn't of any concern, it's what the value of B power B is that matters.
343 is 7 cubed, 7 power 3. Now A power B = 343 = 7 power 3. We do not necessarily know that A = 7 or that B = 3 at this point.
Substitute into that A power C = 7 ("using the info provided"), and you get A power B = (A power C) power 3. Use the power rule to make A power B = A power 3C. Now you have an equation with the same base (whatever that value of the base is), so the two powers have to be equal.
So B = 3C. Go back to B power B. Substitute in 3C for the exponent B: B power B = B power 3C. Use the power rule again, using its inverse, to get B power B = (B power C) power 3. The second given equation is B power C = 10, substitute that into the parentheses.
B power B = (10) power 3. At no time do we know the actual values of A, B, or C, nor care.
A^B = 343. That only has one answer. It must be 7^3 = 343. So A=7 and B=3 (when its used as a power).
A^C = 7. Since we know A=7, 7^C=7. So, C=1.
Now, B^C = 10. Since we don't know what B is when its used as a Base number we have to plug in C. B^1 = 10. So B=10 when used as a base.
Now B^B = 10^3 = 1,000.
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Re: Interesting Math Problems
But, the question should be worded:
A^b = 343
B^c = 10
A^c = 7
What is B^b?
A^b = 343
B^c = 10
A^c = 7
What is B^b?
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Re: Interesting Math Problems
AB = BA
Z -- X -- whole lotta text above the line
ABCD -- DCBA
ABCDEFG
wasn't that hard... Just have to keep the tags straight.
AB = 343, BC = 10, AC = 7. What is BB?
Z -- X -- whole lotta text above the line
ABCD -- DCBA
ABCDEFG

AB = 343, BC = 10, AC = 7. What is BB?
If you can't be a good example, you can still serve as a horrible warning.
“All mushrooms are edible. Some even more than once!”
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“All mushrooms are edible. Some even more than once!”
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Re: Interesting Math Problems
No, and here's why: this is a question from a national mathematics olympiad. These questions are designed around two strict ideas, one that you come to the answer as quickly as possible, and two that you use the problem and given facts about the problem as efficiently and fully as possible in accordance with using best math solving strategies. You can still have the right answer and be marked wrong due to how badly the judges see you use the given info or where your strategy forks. These kinds of questions do not have extraneous information, and the information is meant to be used completely towards answering the problem. You are not supposed to re-think or question the information, you don't have time for that shit.
Going back to the original question, you were given the question of what BB is based on the three given equalities. You can solve for the answer without bothering to try to answer what the exact values of A, B, and C are. You don't need to worry about their values, because you can use the given equalities to do that. Can you tell me what number B is that B multiplied by itself B times would make 1000? Equivalently, can you tell me what number B is that [B x log B = 3]? No, but using the given equalities gets you around that.
You said that AB = 343 = 73 means A = 7 and B = 3. That could be true, but it could also be the logarithmic equivalent of dividing by a hidden zero. The valid step is to make the bases both be A on either side of the equation. That way you don't need to know what the value of A ever is directly. But since they are the same base A, their exponents are equal. That's valid, and we never need to concern ourselves with whether A really is 7 or not.
If you can't be a good example, you can still serve as a horrible warning.
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。
“All mushrooms are edible. Some even more than once!”
これを グーグル 翻訳に登録してくれておめでとう、バカ。